Problem 6.21a
Verify that the Ricker wavelet in Figure 6.21a(i),
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(6.21a)
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, being the peak frequency, has the Fourier transform [Figure 6.21a(ii)]
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(6.21b)
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where
is the phase.
Background
Fourier transforms are discussed in problem 9.3 and theorems on Fourier transforms in Sheriff and Geldart, 1995, section 15.2.6.
The transform of
is
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(6.21c)
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[Papoulis, 1962: p. 25, equation (2-68)].
Figure 6.21a. Ricker wavelet (i) in time domain and (ii) in frequency domain.
Solution
The time-domain expression for the Ricker wavelet can be written in the form
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(6.21d)
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where
. The transform of the first term is
. To get the transform of the second term, we use Sheriff and Geldart, 1995, equation (15.142) which states that when
, then,
that is, for
,
The transform of the second term now becomes
Adding the two transforms, we have
Problem 6.21b
Show that
is the peak of the frequency spectrum.
Solution
To find the peak frequency, we set the derivative
equal to zero. Thus, omitting the constant factor,
so
for a maximum.
Problem 6.21c
Show that
(see Figure 6.21a) and that
Solution
Since
for
, we have
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(6.21e)
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hence
.
Moreover,
is a minimum for
, so
is a root of
that is, of the equation
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(6.21f)
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Hence,
and
.
Continue reading
Also in this chapter
External links
find literature about Ricker wavelet relations
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