Poission’s ratio from P- and S-wave traveltimes

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Problem 13.7

Find Poisson’s ratio for the five events in Figure 13.7a.

Solution

Poisson’s ratio $ \sigma $ can be obtained from the ratio $ V_{\hbox{P}}/V_{\hbox{S}} $ using equation (10.2) Table 2.2a. Since $ z=V_{\hbox{P}}t_{\hbox{P}}=V_{\hbox{S}}t_{\hbox{S}} $, $ V_{\hbox{P}}/V_{\hbox{S}}=t_{\hbox{S}}/t_{\hbox{P}} $, we can get $ (V_{\hbox{P}}/V_{\hbox{S}}) $ from the traveltimes and then get $ \sigma $ using equation (10,2) (see Table 2.2a), that is,

$ {\begin{aligned}\sigma ={\frac {(V_{\hbox{P}}/V_{\hbox{S}})^{2}-2}{2[(V_{\hbox{P}}/V_{\hbox{S}})^{2}-1]}}.\end{aligned}} $

Measurements and calculations are listed in Table 13.7a.

Figure 13.7a.  Comparison of P- and S-wave records (courtesy of CGG.) (i) P-wave record; (ii) S-wave record displayed at double the speed to facilitate comparison.
Table 13.7a. Determination of $ \sigma $.
Event $ t_{\hbox{P}} $ $ t_{\hbox{S}} $ $ \alpha /\beta $ $ (\alpha /\beta )^{2} $ $ \sigma $
1 0.39 0.96 2.46 6.05 0.40
2 0.62 1.50 2.42 5.86 0.40
3 0.74 1.65 2.23 4.97 0.37
4 0.80 1.83 2.29 5.24 0.38
5 0.99 2.16 2.18 4.75 0.37

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Poission’s ratio from P- and S-wave traveltimes