Parallelism of half-intercept and delay-time curves

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Problem 11.10

Prove that a half-intercept curve is parallel to the curve of the total delay time $ \delta $ (see Figure 11.10a).

Solution

Referring to Figure 11.10a, we can write

$ {\begin{aligned}t_{i}/2=h\left(\cos \theta _{c}/V_{1}\right)\end{aligned}} $

Figure 11.10a.  Delay-time and half-intercept curves.

[see equations (11.9b)]. Thus Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): t_{i} /2 is a linear function of Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): h with slope Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): \left(\cos \theta _{c} /V_{1} \right) . The total delay time is

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): \begin{align} \delta=\delta_{s} +\delta_{g}, \end{align}

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): \delta_{s} being constant. If we substitute Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): N=h\tan \theta _{c} (see Figure 11.9a) in equation (11.8a), we obtain the result


Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): \begin{align} \delta_{g} =h\left(\cos \theta _{c} /V_{1} \right), \\ \hbox{so}\quad \quad \delta=\delta_{s} +h\left(\cos \theta _{c} /V_{1} \right). \end{align}

Thus the total delay-time curve is parallel to the half-intercept time curve and lies above it the distance Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): \delta_{s} .

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Parallelism of half-intercept and delay-time curves