Translations:Inverse Fourier transform/21/en

${\begin{aligned}h_{n}={\frac {\mathrm {sin} \Omega _{2}n}{\pi n}}-{\frac {\mathrm {sin} \Omega _{1}n}{\pi n}},n=0,\pm {1,}\pm {2,}...\end{aligned}}$

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