Translations:Frequency response of a digital system/18/es

${\begin{aligned}H\left(e^{-i\omega \Delta t}\right)={\frac {{\beta }_{0}+{\beta }_{1}e^{-i\omega \Delta {\rm {t}}}+{\beta }_{2}e^{-i\omega \Delta t2}+\ldots +{\beta }_{q}e^{-i2\omega \Delta tq}}{1+{\alpha }_{1}e^{-i\omega \Delta t}+{\alpha }_{2}e^{-{\rm {i\omega }}\Delta t2}{\rm {+\ldots +}}{\alpha }_{p}e^{-i\omega \Delta tp}}},\end{aligned}}$

(75)