# Difference between revisions of "Cauchy Integral theorem"

(Created page with "The Cauchy Integral theorem states that for a function <math> f(z) </math> which is analytic inside and on a simple closed curve <math> C </math> in some region <math> {\m...") |
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Because the derivative of an analytic function is also analytic, the integral vanishes identically within a neighborhood of <math> z = a </math>. | Because the derivative of an analytic function is also analytic, the integral vanishes identically within a neighborhood of <math> z = a </math>. | ||

− | By Cauchy's theorem, the contour of integration may be expanded to any closed curve within {\mathcal R} that contains the point <math> z = a</math> | + | By Cauchy's theorem, the contour of integration may be expanded to any closed curve within <math> {\mathcal R} </math> that contains the point <math> z = a</math> |

thus showing that the integral is identically zero. | thus showing that the integral is identically zero. |

## Revision as of 16:58, 17 August 2021

The Cauchy Integral theorem states that for a function which is analytic inside and on a simple closed curve in some region of the complex plane, for a complex number inside

Proof:

For a constant, we may rewrite , and noting that and , and taking the contour of integration to be a circle of unit radius , we may write

.

By Cauchy's Theorem, we may deform the contour into any closed curve that contains the point and the result holds.

For the case when is not constant we may write

.

We must show that the second term on the left is identically zero.

In a vanishingly small neighborhood

.

Because the derivative of an analytic function is also analytic, the integral vanishes identically within a neighborhood of .
By Cauchy's theorem, the contour of integration may be expanded to any closed curve within that contains the point
thus showing that the integral is identically zero.